12x^2+6x-4=2

Solution for 12x^2+6x-4=2 equation:

12x^2+6x-4=2

We move all terms to the left:

12x^2+6x-4-(2)=0

We add all the numbers together, and all the variables

12x^2+6x-6=0

a = 12; b = 6; c = -6;
Δ = b2-4ac
Δ = 62-4·12·(-6)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-18}{2*12}=\frac{-24}{24}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+18}{2*12}=\frac{12}{24}
=1/2
$